1:
a:\(\dfrac{5}{6}=1-\dfrac{1}{6};\dfrac{6}{7}=1-\dfrac{1}{7}\)
Ta có: 6<7
=>\(\dfrac{1}{6}>\dfrac{1}{7}\)
=>\(-\dfrac{1}{6}< -\dfrac{1}{7}\)
=>\(-\dfrac{1}{6}+1< -\dfrac{1}{7}+1\)
=>\(\dfrac{5}{6}< \dfrac{6}{7}\)
b: -11,2023<0
0<1,2022
Do đó: -11,2023<1,2022
2: \(\dfrac{-13}{5}+\dfrac{8}{5}-\dfrac{2}{7}\cdot\dfrac{-14}{5}\)
\(=-\dfrac{5}{5}+\dfrac{28}{35}=-1+\dfrac{4}{5}=-\dfrac{1}{5}\)
