\(\overrightarrow{MQ}=\left(400;200;2\right)\)
Vectơ vận tốc chuyển động có tọa độ:
\(\overrightarrow{v}=\dfrac{\overrightarrow{MQ}}{10}=\dfrac{\left(400;200;2\right)}{10}=\left(40;20;0,2\right)\) \(\left(km/phút\right)\)
Ta có thời gian từ \(M\rightarrow N\) là \(30\left(phút\right)\)
\(\Rightarrow\overrightarrow{MN}=30.\overrightarrow{v}=30.\left(40;20;0,2\right)=\left(1200;600;6\right)\)
\(\Leftrightarrow\left(a-1000;b-600;c-14\right)=\left(1200;600;6\right)\)
\(\Leftrightarrow\left\{{}\begin{matrix}a-1000=1200\\b-600=600\\c-14=6\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}a=2200\\b=1200\\c=20\end{matrix}\right.\) \(\Leftrightarrow N\left(2200;1200;20\right)\)
\(\Rightarrow S=a+b+2c=2200+1200+2.20=3440\)
