a) Ta có:
\(\overrightarrow{AC}-\overrightarrow{AD}=\overrightarrow{DC}\)
\(\overrightarrow{BC}-\overrightarrow{BD}=\overrightarrow{DC}\)
=> \(\overrightarrow{BC}-\overrightarrow{BD}=\overrightarrow{AC}-\overrightarrow{AD}\)
=> \(\overrightarrow{AC}+\overrightarrow{BD}=\overrightarrow{AD}+\overrightarrow{BC}\)
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