Question

Answer 1

\(g)x+\dfrac{1}{12}=\dfrac{-3}{8}\\ x=-\dfrac{3}{8}-\dfrac{1}{12}\\ x=-\dfrac{11}{24}\\ h)x+\dfrac{1}{12}=\dfrac{-11}{12}\\ x=\dfrac{-11}{12}-\dfrac{1}{12}\\ x=\dfrac{-12}{12}\\ x=-1\\ j)\dfrac{1}{6}+x=\dfrac{5}{12}\\ x=\dfrac{5}{12}-\dfrac{1}{6}\\ x=\dfrac{5}{12}-\dfrac{2}{12}\\ x=\dfrac{1}{4}\\ k)\dfrac{4}{7}+x=\dfrac{5}{3}\\ x=\dfrac{5}{3}-\dfrac{4}{7}\\ x=\dfrac{23}{21}\\ m)\dfrac{2}{3}+x=\dfrac{4}{7}\\ x=\dfrac{4}{7}-\dfrac{2}{3}\\ x=-\dfrac{2}{21}\\ n)-\dfrac{5}{9}+x=\dfrac{4}{9}\\ x=\dfrac{4}{9}+\dfrac{5}{9}\\ x=\dfrac{9}{9}=1\)