Question

Answer 1

\(\left(\dfrac{-2}{5}\right)^2.\dfrac{-9}{11}-\dfrac{29}{25}.\dfrac{-6}{11}+\dfrac{4}{25}.\dfrac{3}{11}\)

\(=\dfrac{4}{25}.\dfrac{-9}{11}+\dfrac{29}{25}.\dfrac{6}{11}+\dfrac{2}{25}.\dfrac{6}{11}\)

\(=\dfrac{6}{25}.\dfrac{-6}{11}+\dfrac{6}{25}.\dfrac{29}{11}+\dfrac{6}{25}.\dfrac{2}{11}\)

\(=\dfrac{6}{25}.\left(\dfrac{-6}{11}+\dfrac{29}{11}+\dfrac{2}{11}\right)\)

\(=\dfrac{6}{25}.\dfrac{25}{11}=\dfrac{6}{11}\)