c) \(-\dfrac{1}{4}.x+75\%.x+\dfrac{2}{3}=\dfrac{1}{5}\) 50x3 - 2x = 0
\(x.\left(\dfrac{-1}{4}+\dfrac{75}{100}\right)+\dfrac{2}{3}=\dfrac{1}{5}\) 503x - 2x = 0
\(x.\dfrac{1}{2}+\dfrac{2}{3}\) \(=\dfrac{1}{5}\) x. (503- 2) = 0
\(x.\dfrac{1}{2}\) \(=\dfrac{1}{5}-\dfrac{2}{3}\) x. ( 125000 - 2 ) = 0
\(x.\dfrac{1}{2}\) \(=\dfrac{3}{15}-\dfrac{10}{15}\) x . 124998 = 0
\(x.\dfrac{1}{2}\) \(=\dfrac{-7}{15}\) x = 0 : 124998
\(x\) \(=\dfrac{-7}{15}:\dfrac{1}{2}\) x = 0
\(x\) \(=\dfrac{-7}{15}.\dfrac{2}{1}\) Vậy x = 0
\(x\) \(=\dfrac{-14}{15}\)
Vậy x =\(\dfrac{-14}{15}\)
