Câu 6:
a/ \(=\frac{2(\frac{1}{3}-\frac{1}{5}+\frac{1}{10})}{8(\frac{1}{3}-\frac{1}{5}+\frac{1}{10})}+\frac{1}{2}=\frac{2}{8}+\frac{1}{2}=\frac{1}{4}+\frac{1}{2}=\frac{3}{4}\)
b/ \(=\frac{\frac{1}{3}-\frac{1}{5}+\frac{1}{10}}{6(\frac{1}{3}-\frac{1}{5}+\frac{1}{10})}+\frac{5}{6}=\frac{1}{6}+\frac{5}{6}=1\)
c/ \(=\frac{\frac{1}{2021}+\frac{1}{2022}-\frac{1}{2023})}{5(\frac{1}{2021}+\frac{1}{2022}-\frac{1}{2023})}-\frac{6}{5}=\frac{1}{5}-\frac{6}{5}=-1\)
d/ \(=\frac{\frac{5}{34}-\frac{13.5}{14.17}+\frac{15}{238}}{\frac{-10}{34}+\frac{2.13.5}{14.17}-\frac{15}{119}}=\frac{\frac{5}{34}-\frac{13.5}{14.17}+\frac{15}{238}}{-2(\frac{5}{34}-\frac{13.5}{14.17}+\frac{15}{238})}=\frac{1}{-2}\)
