\(5\left(x-1\right)^2+4^2=\left(-6\right)^2\)
=>\(5\left(x-1\right)^2+16=36\)
=>\(5\left(x-1\right)^2=20\)
=>\(\left(x-1\right)^2=4\)
=>\(\left[{}\begin{matrix}x-1=2\\x-1=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)
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2(5+2x)3−7=−92(5+2�)3−7=−9
=>2(2x+5)3=−9+7=−22(2�+5)3=−9+7=−2
=>(2x+5)3=−1(2�+5)3=−1
=>2x+5=-1
=>2x=-6
=>x=-6/2=-3
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