Câu 37 :
\(n_{HCl}=1,5.0,05=0,075\left(mol\right)\)
1) PTHH : \(KOH+HCl\rightarrow KCl+H_2O\)
Theo Pt : \(n_{HCl}=n_{KOH}=n_{KCl}=0,075\left(mol\right)\)
2) \(V_{ddKOH}=\dfrac{0,075}{2}=0,0375\left(l\right)\)
3) \(C_{MKCl}=\dfrac{0,075}{0,0375+0,05}=\dfrac{6}{7}\left(M\right)\)
\(1.KOH+HCl\rightarrow KCl+H_2O\\ 2.n_{HCl}=0,05.1,5=0,075mol\\ n_{KOH}=n_{KCl}=n_{HCl}=0,075mol\\ V_{ddKOH}=\dfrac{0,075}{2}=0,0375l\\ 3.C_{M_{KCl}}=\dfrac{0,075}{0,0375+0,05}=\dfrac{6}{7}M\)