\(n_{Zn}=\dfrac{9,75}{65}=0,15mol\\ n_{Al}=\dfrac{2,7}{27}=0,1mol\\ n_{HNO_3}=2,5.0,2=0,5mol\\ n_{H_2SO_4}=0,75.0,2=0,15mol\\ BTe:2n_{Zn}+3n_{Al}=3n_{NO}\\ \Leftrightarrow2.0,15+3.0,1=3n_{NO}\\ \Leftrightarrow n_{NO}=0,2mol\\ n_{NO_3^-}=0,5-0,2=0,3mol\\ n_{SO_4^-}=n_{H_2SO_4}=0,15mol\\ m_{muối}=9,75+2,7+0,3.62+0,15.96=45,45g\)