a: =-27*0:(3+1/4-1-1/6)
=0
b: \(=\left[\dfrac{-193}{17}\cdot\dfrac{1}{386}+\dfrac{11}{34}\right]:\left(\dfrac{14+11}{3862}\cdot\dfrac{1931}{25}+\dfrac{9}{2}\right)\)
\(=\left(\dfrac{-1}{34}+\dfrac{11}{34}\right):\left(\dfrac{1}{2}+\dfrac{9}{2}\right)=\dfrac{5}{17}:5=\dfrac{1}{17}\)