\(a,\dfrac{4}{7}.x+\dfrac{2}{3}=\dfrac{-1}{5}\\ \dfrac{4}{7}x=\dfrac{-1}{5}-\dfrac{2}{3}\\ \dfrac{4}{7}x=\dfrac{-13}{15}\\ x=\dfrac{-13}{15}:\dfrac{4}{7}\\ x=\dfrac{-91}{60}\\ b,\dfrac{2}{9}-\dfrac{7}{8}x=1\\ \dfrac{7}{8}x=\dfrac{2}{9}-1\\ \dfrac{7}{8}x=\dfrac{-7}{9}\\ x=\dfrac{-8}{9}\\ c,\dfrac{4}{5}+\dfrac{7}{6}:x=\dfrac{1}{6}\\ \dfrac{7}{6}:x=\dfrac{1}{6}-\dfrac{4}{5}\\ \dfrac{7}{6}:x=\dfrac{-19}{30}\\ x=\dfrac{7}{6}:\dfrac{-19}{30}\\ x=\dfrac{-35}{19}\\\dfrac{5}{7}:x-1=\dfrac{2}{3}\\ \dfrac{5}{7}:x=\dfrac{2}{3}+1\\\dfrac{5}{7}:x=\dfrac{5}{3}\\ x=\dfrac{5}{7}:\dfrac{5}{3}\\ x=\dfrac{3}{7} \)
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