Question

Answer 1

a) Ta có: Oz là tia phân giác của \(\widehat{xOy}\)(gt)

nên \(\widehat{xOz}=\dfrac{\widehat{xOy}}{2}=\dfrac{120^0}{2}=60^0\)

Vậy: \(\widehat{xOz}=60^0\)

Answer 2

b) Ta có: \(\widehat{xOy}+\widehat{mOy}=180^0\)(hai góc kề bù)

\(\Leftrightarrow\widehat{mOy}+120^0=180^0\)

hay \(\widehat{mOy}=60^0\)

Vậy: \(\widehat{mOy}=60^0\)