\(\left|\overrightarrow{AB}-\overrightarrow{AD}\right|=\left|\overrightarrow{AB}+\overrightarrow{DA}\right|=\left|\overrightarrow{DB}\right|=DB=AC\\ AC=\sqrt{a^2+\left(2a\right)^2-2.a.2a.cos120^o}=\sqrt{3}a=BD\\ =>\left|\overrightarrow{AB}-\overrightarrow{AD}\right|=\sqrt{3}a\)