\(\dfrac{4+\dfrac{4}{73}-\dfrac{4}{115}}{5+\dfrac{5}{73}-\dfrac{1}{23}}-4:\left(9-2:0,5\right)=\dfrac{4.\left(1+\dfrac{1}{73}-\dfrac{1}{115}\right)}{5.\left(1+\dfrac{1}{73}-\dfrac{1}{115}\right)}-4:\left(9-4\right)=\dfrac{4}{5}-4:5=\dfrac{4}{5}-\dfrac{4}{5}=0\)