a)
Ta có:
2\(^{24}\)=(2\(^{12}\))\(^2\)=4096\(^2\)
3\(^{16}\)=(3\(^8\))\(^2\)=6561\(^2\)
Mà: 4096\(^2\)<6561\(^2\)
Nên 2\(^{24}\)<3\(^{16}\)
b) \(2^{300}\)và \(3^{200}\)
ta có :
2\(^{300}\)=(2\(^3\))\(^{100}\)=8\(^{100}\)
3\(^{200}\)=(3\(^2\))\(^{100}\)=9\(^{100}\)
vì 8\(^{100}\)<9\(^{100}\) nên \(2^{300}< 3^{200}\)