\(n_{NO}=a\left(mol\right),n_{N_2O}=b\left(mol\right)\)
\(n_{hh}=a+b=\dfrac{2.24}{22.4}=0.1mol\)
\(m_{hh}=30a+44b=0.1\cdot19.9=1.99\left(g\right)\)
\(\Rightarrow a=0.03,b=0.07\)
Bảo toàn e :
\(n_{Al}=\dfrac{3\cdot0.03+8\cdot0.07}{3}=\dfrac{13}{60}\left(mol\right)\)
\(m_{Al}=\dfrac{13}{60}\cdot27=5.85\left(g\right)\)