Question

Answer 1

\(1,S_{MNP}=\dfrac{1}{2}\left(MN.MP\right)=\dfrac{1}{2}\cdot\left(20.50\right)\\ =500\left(cm^2\right)\)

\(2,S_{MNC}=\dfrac{1}{2}\left(AC.MN\right)=\dfrac{1}{2}\left(40.20\right)=400\left(cm^2\right)\)

Answer 2

giúp tớ với tớ đang cần lắm

 

Answer 3

a) Có: \(MP=MB+BP=40+10=50\left(cm\right)\)

\(\Rightarrow S_{MNP}=20\times50:2=500\left(cm^2\right)\)

b) Vì \(MACB\) là HCN

\(\Rightarrow AC=MB=40\left(cm\right)\)

\(\Rightarrow S_{MNC}=40\times20:2=400\left(cm^2\right)\)

c) Đg nghĩ

Answer 4

c) Có: \(S_{MNP}-S_{MNC}=500-400=100\left(cm^2\right)=S_{MCP}\)

\(\Rightarrow CB=100\times2:50=4\left(cm\right)\)