Question

Answer 1

\(\left(a\right):9x^2-12x+4=\left(3x\right)^2-2.3x.2+2^2=\left(3x-2\right)^2\\ \left(b\right):25+10x+x^2=x^2+2.x.5+5^2=\left(x+5\right)^2\\ \left(c\right):36x^2-25=\left(6x\right)^2-5^2=\left(6x-5\right)\left(6x+5\right)\\ \left(d\right):x^3-3x^2y+3xy^2-1=\left(x-1\right)^3\)

Answer 2

a) \(9x^2-12x+4=\left(3x-2\right)^2\)

b) \(25+10x-x^2=-\left(x^2-10x+25\right)=-\left(x-5\right)^2\)

c) \(36x^2-25=\left(6x\right)^2-5^2=\left(6x-5\right)\left(6x+5\right)\)

d) \(x^3-3x^2y+3xy^2-y^3=\left(x-y\right)^3\)