\(\left(0,25\right)^3.32=\left(\dfrac{1}{4}\right)^3.2^5=\dfrac{1}{2^6}.2^5=\dfrac{1}{2}\)
\(\left(-0,125\right)^3.80^4=\left(-\dfrac{1}{8}\right)^3.10^4.8^4=-8.10^4=\left(-2\right)^3.10^4\)
\(\dfrac{8^2.4^5}{2^{20}}=\dfrac{\left(2^3\right)^2.\left(2^2\right)^5}{2^{20}}=\dfrac{2^6.2^{10}}{2^{20}}=2^4=16\)
\(\dfrac{81^{11}.3^{17}}{27^{10}.9^{15}}=\dfrac{\left(3^4\right)^{11}.3^{17}}{\left(3^3\right)^{10}.\left(3^2\right)^{15}}=\dfrac{3^{44}.3^{17}}{3^{30}.3^{30}}=\dfrac{3^{61}}{3^{60}}=3\)
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