BT2:
\(n_{CO_2}=\dfrac{11,2}{22,4}=0,5\left(mol\right)\)
PTHH: CH4 + 2O2 --to--> CO2 + 2H2O
0,5--->1
=> m = 1.18 = 18 (g)
BT3:
\(n_{CO_2}=\dfrac{22,4}{22.4}=1\left(mol\right)\)
PTHH: C2H4 + 3O2 --to--> 2CO2 + 2H2O
1----->1
=> m = 1.18 = 18 (g)
BT2:
\(n_{CH_4}=\dfrac{16}{16}=1\left(mol\right)\)
\(CH_4+2O_2\underrightarrow{t^o}CO_2+2H_2O\)
\(m=mH_2O=1.2.18=36\left(g\right)\)
BT3:
\(nC_2H_4=\dfrac{14}{28}=0,5\left(mol\right)\)
\(C_2H_4+3O_2\underrightarrow{t^o}2CO_2+2H_2O\)
\(m=mH_2O=0,5.2.18=18\left(g\right)\)
PTHH: C2H4 + 3O2 --to--> 2CO2 + 2H2O
1----->1
=> m = 1.18 = 18 (g)