a: \(=\dfrac{2}{7}-\dfrac{1}{5}\cdot2=\dfrac{2}{7}-\dfrac{2}{5}=\dfrac{10-14}{35}=\dfrac{-4}{35}\)
b: \(=\dfrac{4}{9}\cdot\dfrac{-3}{8}+\dfrac{1}{18}=\dfrac{-1}{6}+\dfrac{1}{18}=\dfrac{-3+1}{18}=\dfrac{-1}{9}\)
c: \(=\dfrac{3-4}{6}\cdot\dfrac{4}{5}=\dfrac{-1}{6}\cdot\dfrac{4}{5}=\dfrac{-2}{15}\)
d: \(=\dfrac{10-3}{12}:\dfrac{3+4}{6}=\dfrac{7}{12}\cdot\dfrac{6}{7}=\dfrac{1}{2}\)