\(=\dfrac{3}{23}+\dfrac{1}{46}=\dfrac{6}{46}+\dfrac{1}{46}=\dfrac{7}{46}\)
`1 / 24 xx 72 / 23 + 1 / 46`
`= [ 1 xx 3 xx 24 ] / [ 24 xx 23 ] + 1 / 46`
`= 3 / 23 + 1 / 46`
`= 6 / 46 + 1 / 46`
`= 7 / 46`
\(\dfrac{1}{24}\)x\(\dfrac{73}{23}+\dfrac{1}{46}\)
= \(\dfrac{3}{23}+\dfrac{1}{46}\)
\(\dfrac{7}{46}\)