Question

Answer 1

\(=>\left(1-\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{4}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{5}...+\dfrac{1}{8}-\dfrac{1}{9}+\dfrac{1}{10}\right).x=\dfrac{22}{45}\)

\(=>\left(\dfrac{10}{10}-\dfrac{1}{10}\right).x=\dfrac{22}{45}\)

\(=>\dfrac{9}{10}x=\dfrac{22}{45}\)

\(=>x=\dfrac{22}{45}:\dfrac{9}{10}=\dfrac{44}{81}\)