\(\Leftrightarrow21x=7x-84\)
\(\Leftrightarrow21x-7x+84=0\)
\(\Leftrightarrow14x=-84\)
\(\Leftrightarrow x=-6\)
\(\dfrac{3x}{21}=\dfrac{x-12}{21}\)
=> 3x=x-12
3x-x=x-12-x
2x=-12
x=-6
\(\dfrac{x}{7}=\dfrac{x-12}{21}\)
\(⇔21x=7(x-12)\)
\(⇔21x-7x=-84\)
\(⇔14x=-84\)
\(⇔x=-6\)
