\(=>x\left(\dfrac{8}{9}+\dfrac{4}{9}-\dfrac{7}{9}\right)=\dfrac{11}{10}\)
\(=>x\times\dfrac{5}{9}=\dfrac{11}{10}\)
\(=>x=\dfrac{11}{10}\times\dfrac{9}{5}=\dfrac{99}{50}\)
theo đề ta có \(\dfrac{8x}{9}+\dfrac{4x}{9}-\dfrac{7x}{9}=\dfrac{11}{10}\)
\(\dfrac{8x+4x-7x}{9}=\dfrac{5x}{9}=\dfrac{11}{10}\)
\(\Leftrightarrow50x=99\)
\(\Leftrightarrow x=\dfrac{99}{50}=1,98\)
=> X x(8/9 + 4/9 - 7/9) = 11/10
=> X x 5/9 = 11/10
=>x = 11/10 : 5/9
X= 99/50