\(\dfrac{75}{100}+\dfrac{18}{42}+\dfrac{19}{32}+\dfrac{1}{4}+\dfrac{4}{7}+\dfrac{26}{64}=\dfrac{3}{4}+\dfrac{3}{7}+\dfrac{19}{32}+\dfrac{1}{4}+\dfrac{4}{7}+\dfrac{13}{32}=\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+\left(\dfrac{3}{7}+\dfrac{4}{7}\right)+\left(\dfrac{19}{31}+\dfrac{13}{21}\right)=\dfrac{4}{4}+\dfrac{7}{7}+\dfrac{32}{32}=1+1+1=3\)