Question

Answer 1

a) \(\dfrac{-5}{8}+\dfrac{-11}{8}=\dfrac{-16}{8}=-2\)

b) \(2\dfrac{1}{3}\div7=\dfrac{7}{3}\div7=\dfrac{7}{3}\cdot\dfrac{1}{7}=\dfrac{7}{21}=\dfrac{1}{3}\)

c) \(\dfrac{5}{12}+\dfrac{-8}{15}+\dfrac{3}{29}+\dfrac{-7}{15}+\dfrac{7}{12}=\left(\dfrac{5}{12}+\dfrac{7}{12}\right)+\left(\dfrac{-8}{15}+\dfrac{-7}{15}\right)+\dfrac{3}{29}=1+\left(-1\right)+\dfrac{3}{29}=\dfrac{3}{29}\)

d) \(\dfrac{5}{9}\cdot\dfrac{7}{13}+\dfrac{5}{9}\cdot\dfrac{9}{13}-\dfrac{3}{13}\cdot\dfrac{5}{9}=\dfrac{5}{9}\cdot\left(\dfrac{7}{13}+\dfrac{9}{13}-\dfrac{3}{13}\right)=\dfrac{5}{9}\cdot\dfrac{13}{13}=\dfrac{5}{9}\cdot1=\dfrac{5}{9}\)