a.\(=\dfrac{3+4}{7}+\dfrac{5}{6}=1+\dfrac{5}{6}=\dfrac{11}{6}\)
b.\(=\dfrac{6+5}{11}+\dfrac{1}{3}=1+\dfrac{1}{3}=\dfrac{4}{3}\)
c.\(=\dfrac{4+5}{9}+\dfrac{2}{5}=1+\dfrac{2}{5}=\dfrac{7}{5}\)
\(a,\dfrac{3}{7}+\dfrac{5}{6}+\dfrac{4}{7}=1+\dfrac{5}{6}=\dfrac{11}{6}\\ b,\dfrac{6}{11}+\dfrac{1}{3}+\dfrac{5}{11}=1+\dfrac{1}{3}=\dfrac{4}{3}\\ c,\dfrac{4}{9}+\left(\dfrac{2}{5}+\dfrac{5}{9}\right)=\left(\dfrac{4}{9}+\dfrac{5}{9}\right)+\dfrac{2}{5}=1+\dfrac{2}{5}=\dfrac{7}{5}\)
a. = 11/6
b. = 4/3
c. = 7/5
k mik nha bn