\(pthh:2Mg+O_2\overset{t^o}{--->}2MgO\left(1\right)\)
Ta có: \(n_{Mg}=2,\dfrac{4}{24}=0,1\left(mol\right)\)
a. Theo pt(1): \(n_{O_2}=\dfrac{1}{2}.n_{Mg}=\dfrac{1}{2}.0,1=0,05\left(mol\right)\)
\(\Rightarrow V_{O_2}=0,05.22,4=1,12\left(lít\right)\)
b. \(pthh:2KClO_3\xrightarrow[t^o]{MnO_2}2KCl+3O_2\left(2\right)\)
Theo pt(2): \(n_{KClO_3}=\dfrac{2}{3}.n_{O_2}=\dfrac{2}{3}.0,05=\dfrac{1}{30}\left(mol\right)\)
\(\Rightarrow m_{KClO_3}=\dfrac{1}{30}.122,5\approx4,083\left(g\right)\)
Đúng 2
Bình luận (0)
