a: \(2Al+3O_2\rightarrow2Al_2O_3\)
\(n_{Al}=\dfrac{5.4}{27}=0.2\left(mol\right)\)
\(n_{Al_2O_3}=0.1\left(mol\right)\)
\(\Leftrightarrow n_{O_2}=0.15\left(mol\right)\)
\(V_{O_2}=0.15\cdot22.4=3.36\left(lít\right)\)
b: \(m_{Al_2O_3}=0.1\cdot102=10.2\left(g\right)\)
Bài 1 :
\(n_{Al}=\dfrac{5,4}{27}=0,2\left(mol\right)\)
Pt : \(4Al+3O_2\underrightarrow{t^o}2Al_2O_3|\)
4 3 2
0,2 0,15 0,1
a) \(n_{O2}=\dfrac{0,2.3}{4}=0,15\left(mol\right)\)
\(V_{O2\left(dktc\right)}=0,15.22,4=3,36\left(l\right)\)
b) \(n_{Al2O3}=\dfrac{0,15.2}{3}=0,1\left(mol\right)\)
⇒ \(m_{Al2O3}=0,1.102=10,2\left(g\right)\)
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