a) \(n_{H_2}=\dfrac{4,48}{22,4}=0,2\left(mol\right)\)
PTHH: Zn + 2HCl --> ZnCl2 + H2
0,2<-------------0,2<----0,2
=> mZn = 0,2.65 = 13 (g)
=> \(m_{Al_2O_3}=18,1-13=5,1\left(g\right)\)
b) \(n_{Al_2O_3}=\dfrac{5,1}{102}=0,05\left(mol\right)\)
PTHH: Al2O3 + 6HCl --> 2AlCl3 + 3H2O
0,05------------->0,1
=> \(\left\{{}\begin{matrix}m_{ZnCl_2}=0,2136=27,2\left(g\right)\\m_{AlCl_3}=0,1.133,5=13,35\left(g\right)\end{matrix}\right.\)
=> mmuối = 27,2 + 13,35 = 40,55 (g)
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