a)xét \(\Delta AFC\)và \(\Delta FEB\)có:
\(AE=FE\left(gt\right)\\ BE=EC\left(gt\right)\\ \widehat{BEF}=\widehat{CEA}\\ \Delta ACF=\Delta FBE\left(c-g-c\right)\)
b) do \(\Delta ACF=\Delta FBE\\ \Rightarrow AC=BF\\ \widehat{ACE}=\widehat{EBF}\)
( so le trong)
\(\Rightarrow AC\)//\(BF\)