Question

Answer 1

a: \(A=\dfrac{-5+3}{9}+\dfrac{3}{5}-\dfrac{2}{5}=\dfrac{-2}{9}+\dfrac{1}{5}=\dfrac{-10+9}{45}=-\dfrac{1}{45}\)

b: \(B=\dfrac{5-2}{17}+\dfrac{-9-6}{15}=\dfrac{3}{17}-1=-\dfrac{14}{17}\)

c: \(C=\dfrac{2+11+1}{7}+\dfrac{-3-5}{8}+\dfrac{1}{3}=\dfrac{1}{3}\)

Answer 2

a) \(A=\dfrac{-5}{9}+\dfrac{3}{5}+\dfrac{-3}{9}+\dfrac{-2}{5}\)
\(A=\left(\dfrac{-5}{9}+\dfrac{-3}{9}\right)+\left(\dfrac{3}{5}+\dfrac{-2}{5}\right)\)
\(A=\dfrac{-8}{9}+\dfrac{1}{5}\)
\(A=\dfrac{-3119}{4005}\)