\(n_{CO_2}=\dfrac{m}{M}=8,8:44=0,2\left(mol\right)\\ V_{CO_2}=n.22,4=4,48\left(l\right)\)
=> Chọn A
á mà khoan thi Azota hay sao mà có màu xanh xanh
nCO2=\(\dfrac{m_{CO2}}{M_{CO2}}=\dfrac{8,8}{44}=0,2\left(mol\right)\\ \)
\(V_{CO2}=n_{CO2}.22,4=0,2.22,4=4,48\left(l\right)\\ \Rightarrow A\)