\(6NaOH+Fe_2\left(SO_{\text{4 }}\right)_3\rightarrow2Fe\left(OH\right)_3+3NaSO_4\)
Mg + 2AgNO\(_3\) → Mg(NO3)\(_2\) + 2Ag
4Na + O\(_2\) → 2Na\(_2\)O
2Al + 6HCl → 2AlCl\(_3\) + 3H\(_2\)
c2 a
\(mFe_3O_4=0,05.232=11,6g\)
b,
\(nSO_2=2,24:22,4=0,1mol\)
\(mSO_2=0,1.64=6,4g\)
c3 khong thấy đc
Bài 1 :
1) 6NaOH + Fe2(SO4)3 -> 2Fe(OH)3 + 3Na2SO4
2) Mg + 2AgNO3 -> Mg(NO3)2 + 2Ag
3) Na + O2 -> NaO2
4) 2Al + 6HCl -> 2AlCl3 + 3H2
Bài 2 :
a) \(m=n.M=0,05.232=11,6\left(g\right)\)
b) \(n=\dfrac{V}{22,4}=\dfrac{2,24}{22,4}=0,1\left(mol\right)\)
\(m=n.M=0,1.64=6,4\left(g\right)\)
