\(2A=2^2+2^3+...+2^{2022}\\ \Rightarrow2A-A=A=2^{2022}-2\\ \Rightarrow2^{2022}-2=2^x-2\\ \Rightarrow x=2022\\ A=2+\left(2^2+2^3\right)+\left(2^4+2^5\right)+...+\left(2^{2020}+2^{2021}\right)\\ A=2+\left(2+1\right)\left(2^2+2^4+...+2^{2020}\right)\\ A=2+3\left(2^2+2^4+...+2^{2020}\right)⋮̸3\left(\text{đề sai}\right)\)