a, x + \(\dfrac{1}{4}\) = \(\dfrac{2}{8}\) + \(\dfrac{3}{8}\)
x + \(\dfrac{1}{4}\) = \(\dfrac{5}{8}\)
x = \(\dfrac{5}{8}\) - \(\dfrac{1}{4}\)
x = \(\dfrac{3}{8}\)
b, 125 x 48 : 10 - 345
= 6000 : 10 - 345
= 600 - 345
= 255
a) Tìm x :
\(x+\dfrac{1}{4}=\dfrac{2}{8}+\dfrac{3}{8}\)
\(x+\dfrac{1}{4}=\dfrac{5}{8}\)
\(x=\dfrac{5}{8}-\dfrac{1}{4}\)
\(x=\dfrac{3}{8}\)
b) Tính giá trị biểu thức
\(125\)x\(48:10-345\)
\(\left(125x48\right):10-345\)
\(6000:10-345\)
\(\left(6000:10\right)-345\)
\(600-345\)
\(255\)
a) x + 1/4 = 2/8 + 3/8
x = 5/8 - 1/4
x = 3/8
b) 125 x 48 : 10 - 345
= 6000 : 10 - 345
= 600 - 345
= 255
4 và 5
