d, \(\dfrac{1}{3}x+\dfrac{3}{5}x=-\dfrac{2}{5}\Leftrightarrow\dfrac{5}{15}x+\dfrac{9}{15}x=-\dfrac{6}{15}\)
\(\Rightarrow14x=-6\Leftrightarrow x=-\dfrac{3}{7}\)
e, \(\dfrac{5}{7}x+\dfrac{2}{3}x=\dfrac{3}{10}\Leftrightarrow\dfrac{150x}{210}+\dfrac{140x}{210}=\dfrac{63}{210}\Rightarrow290x=63\Leftrightarrow x=\dfrac{63}{290}\)