a) \(=\dfrac{1}{2}+\dfrac{1}{4}=\dfrac{2}{4}+\dfrac{1}{4}=\dfrac{3}{4}\)
b) \(=\dfrac{8}{12}+\dfrac{6}{12}-\dfrac{5}{12}=\dfrac{9}{12}=\dfrac{3}{4}\)
a) \(\dfrac{1}{2}+\dfrac{3}{4}x\dfrac{1}{3}=\dfrac{3}{4}\)
b) \(\dfrac{2}{3}+\dfrac{1}{2}-\dfrac{5}{12}=\dfrac{3}{4}\)