Question

Answer 1

Bài 2:

\(\Leftrightarrow x^3-2x^2-x^2+2x+3x-6-2m+6⋮x-2\)

hay m=3

Answer 2

\(1,\\ a,=xy-6y^2+3xz\\ b,=\left(x-3\right)\left(x^2+1\right):\left(x-3\right)=x^2+1\\ 2,\\ \Leftrightarrow x^3-3x^2+5x-2m=\left(x-2\right)\cdot a\left(x\right)\)

Thay \(x=2\Leftrightarrow8-12+10-2m=0\Leftrightarrow m=3\)