Câu hỏi của Đỗ Hà My

\(A=\sqrt{3+\sqrt{\left(\sqrt{12}+\sqrt{1}\right)^2}}\)\(A=\sqrt{3+\left|\sqrt{12}+\sqrt{1}\right|}\)\(A=\sqrt{3+\sqrt{12}+1}\)\(A=\sqrt{4+\sqrt{12}}\)\(A=\sqrt{\left(\sqrt{3}+\sqrt{1}\right)^2}\)\(A=\left|\sqrt{3}+\sqrt{1}\right|\)\(A=\sqrt{3}+1\) Câu trả lời: \(A=\sqrt{3+\sqrt{\left(\sqrt{12}+\sqrt{1}\right)^2}}\)\(A=\sqrt{3+\left|\sqrt{12}+\sqrt{1}\right|}\)\(A=\sqrt{3+\sqrt{12}+1}\)\(A=\sqrt{4+\sqrt{12}}\)\(A=\sqrt{\left(\sqrt{3}+\sqrt{1}\right)^2}\)\(A=\left|\sqrt{3}+\sqrt{1}\right|\)\(A=\sqrt{3}+1\)