\(x:3\dfrac{1}{5}=1\dfrac{1}{2}\)
\(\Leftrightarrow x:\dfrac{16}{5}=\dfrac{3}{2}\)
\(\Leftrightarrow x=\dfrac{16}{15}.\dfrac{3}{2}\)
\(\Leftrightarrow x=\dfrac{8}{5}\)
+) \(\dfrac{2}{5}x+\dfrac{-3}{7}=\dfrac{-1}{5}x+\dfrac{8}{14}\)
\(\Leftrightarrow\dfrac{3}{5}x=1\)
\(\Leftrightarrow x=\dfrac{5}{3}\)
a)\(x:3\dfrac{1}{5}=1\dfrac{1}{2}\)
\(\Rightarrow x:\dfrac{16}{5}=\dfrac{3}{2}\\ \Rightarrow x=\dfrac{3}{2}.\dfrac{16}{5}\\ \Rightarrow x=\dfrac{24}{5}\)
Vậy x=\(\dfrac{24}{5}\)
b)
\(\dfrac{2}{5}x+\dfrac{-3}{7}=\dfrac{-1}{5}x+\dfrac{8}{14}\\ \Rightarrow\dfrac{2}{5}x-\dfrac{-1}{5}x=\dfrac{8}{14}-\dfrac{-3}{7}\\ \)
\(\Rightarrow\dfrac{2}{5}x+\dfrac{1}{5}x=\dfrac{8}{14}+\dfrac{3.2}{7.2}\\ \Rightarrow\dfrac{3}{5}x=\dfrac{8}{14}+\dfrac{6}{14}\\ \Rightarrow\dfrac{3}{5}x=\dfrac{14}{14}\\ \Rightarrow\dfrac{3}{5}x=1\\ \Rightarrow x=1:\dfrac{3}{5}\\ \Rightarrow x=\dfrac{5}{3}\)
Vậy x=\(\dfrac{5}{3}\)
a: Ta có: \(x:3\dfrac{1}{5}=1\dfrac{1}{2}\)
\(\Leftrightarrow x=\dfrac{3}{2}\cdot\dfrac{16}{5}=\dfrac{24}{5}\)
b: Ta có: \(\dfrac{2}{5}x+\dfrac{-3}{7}=\dfrac{-1}{5}x+\dfrac{8}{14}\)
\(\Leftrightarrow x\cdot\dfrac{3}{5}=\dfrac{4}{7}+\dfrac{3}{7}=1\)
hay \(x=\dfrac{5}{3}\)