\(\dfrac{12x25+4x175x3}{\left(36x100\right)-\left(24x100\right)}\)
=\(\dfrac{12x25+12x175}{360-240}\)
=\(\dfrac{12x\left(25+175\right)}{120}\)
=\(\dfrac{12x200}{120}\)
=\(\dfrac{240}{120}\)
=2
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Bài 2:
a.
\(A=\frac{12\times 25+4\times 175\times 3}{(36\times 101-36)-(24\times 99+24)}=\frac{12\times 25+12\times 175}{36\times (101-1)-24\times (99+1)}\)
\(=\frac{12\times (25+175)}{36\times 100-24\times 100}=\frac{12\times 200}{100\times (36-24)}=\frac{2\times 12\times 100}{100\times 12}=2\)
b.
\(A=\frac{12\times 25+12\times m}{36\times (101-1)-24\times (99+1)}=\frac{12\times (25+m)}{36\times 100-24\times 100}\)
\(=\frac{12\times (25+m)}{100\times (36-24)}=\frac{12\times (25+m)}{12\times 100}=\frac{25+m}{100}\)
\(A=\frac{25+m}{100}=10\)
\(25+m=100\times 10\)
\(25+m=1000\)
\(m=1000-25=975\)
\(10=\dfrac{12x25+12xm}{\left(36x100\right)-\left(24x100\right)}\)
\(10=\dfrac{12x\left(25+m\right)}{360-240}\)
\(10=\dfrac{12x\left(25+m\right)}{120}\)
\(10x120=12x\left(25+m\right)\)
\(1200=12x\left(25+m\right)\)
\(1200:12=25+m\)
\(100=25+m\)
\(m=75\)
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