Bài 1:
a) Ta có: \(\dfrac{-3}{7}-\left(\dfrac{2}{3}-\dfrac{3}{7}\right)\)
\(=\dfrac{-3}{7}-\dfrac{2}{3}+\dfrac{3}{7}\)
\(=\dfrac{-2}{3}\)
b) Ta có: \(\dfrac{2}{15}:\left(\dfrac{1}{3}\cdot\dfrac{4}{5}-\dfrac{1}{3}\cdot\dfrac{6}{5}\right)\)
\(=\dfrac{2}{15}:\left(\dfrac{4}{15}-\dfrac{6}{15}\right)\)
\(=\dfrac{2}{15}:\dfrac{-2}{15}\)
\(=\dfrac{2}{15}\cdot\dfrac{15}{-2}=-1\)