Ta có:
\(\left\{{}\begin{matrix}SA\perp\left(ABCD\right)\Rightarrow SA\perp CD\\AD\perp CD\left(gt\right)\end{matrix}\right.\) \(\Rightarrow CD\perp\left(SAD\right)\)
Mà \(AH\in\left(SAD\right)\Rightarrow CD\perp AH\) (1)
Lại có AH là đường cao tam giác SAD \(\Rightarrow AH\perp SD\) (2)
(1);(2) \(\Rightarrow AH\perp\left(SCD\right)\)