Câu 7:
\(\lim\limits_{x\rightarrow-\infty}\dfrac{-3x+1}{x-1}=\lim\limits_{x\rightarrow-\infty}\dfrac{-3+\dfrac{1}{x}}{1-\dfrac{1}{x}}=-3\)
Câu 8:
\(\lim\limits_{x\rightarrow+\infty}\dfrac{1}{x^k}=0\) ; \(\lim\limits_{x\rightarrow-2}\left(x+3\right)=1\) ; \(\lim\limits_{x\rightarrow5}7=7\)