Question

Answer 1

Answer 2

Bài 1:

S=\(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{2004}-\dfrac{1}{2005}\)

S=\(1-\dfrac{1}{2005}\)

S=\(\dfrac{2004}{2005}\)

Answer 3

Bài 1

S=[1/1 - 1/2 + 1/2 -1/3 +1/3 +1/4+....+1/2004 -1/2005]

S=[1/1-1/2005]

S=2004/2005

Answer 4