Bài 1:
Ta có: \(A=\dfrac{2-\dfrac{2}{19}+\dfrac{2}{43}-\dfrac{2}{1943}}{3-\dfrac{3}{19}+\dfrac{3}{43}-\dfrac{3}{1943}}:\dfrac{4-\dfrac{4}{19}+\dfrac{4}{41}-\dfrac{4}{2941}}{5-\dfrac{5}{19}+\dfrac{5}{41}-\dfrac{5}{2941}}\)
\(=\dfrac{2}{3}:\dfrac{4}{5}\)
\(=\dfrac{10}{12}=\dfrac{5}{6}\)
Bài 5:
Ta có: \(B=\left(\dfrac{151515}{161616}+\dfrac{17^9}{17^{10}}\right)-\left(\dfrac{1500}{1600}-\dfrac{176}{187}\right)\)
\(=\dfrac{15}{16}+\dfrac{1}{17}-\dfrac{15}{16}+\dfrac{16}{17}\)
=1
Đúng 2
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