Giải:
\(\dfrac{4.x}{12}+\dfrac{3.x+7}{6}=\dfrac{6-2.x}{3}+\dfrac{7-x}{4}\)
\(\Rightarrow\dfrac{4.x}{12}+\dfrac{2.\left(3.x+7\right)}{12}=\dfrac{4.\left(6-2.x\right)}{12}+\dfrac{3.\left(7-x\right)}{12}\)
\(\Rightarrow\dfrac{\left(4.x\right)+\left(6.x+14\right)}{12}=\dfrac{\left(24-8.x\right)+\left(21-3.x\right)}{12}\)
\(\Rightarrow\left(4.x\right)+\left(6.x+14\right)=\left(24-8.x\right)+\left(21-3.x\right)\)
\(\Rightarrow4.x+6.x+14=24-8.x+21-3.x\)
\(\Rightarrow4.x+6.x+8.x+3.x=24+21-14\)
\(\Rightarrow21.x=31\)
\(\Rightarrow x=31:21\)
\(\Rightarrow x=\dfrac{31}{21}\)
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